Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 372: 60

Answer

$20x^2y^3\sqrt{y} $

Work Step by Step

Extracting the factors that are perfect powers of the index, the given expression is equivalent to \begin{align*}\require{cancel} & =5\sqrt{y^6\cdot2x}\cdot2\sqrt{x^2\cdot2xy} \\\\&= 5\sqrt{(y^3)^2\cdot2x}\cdot2\sqrt{(x)^2\cdot2xy} \\\\&= 5y^3\sqrt{2x}\cdot2x\sqrt{2xy} .\end{align*} Using the rule $a\sqrt{x}\cdot b\sqrt{y}=ab\sqrt{xy},$ the expression above is equivalent to \begin{align*} & =5y^3(2x)\sqrt{2x(2xy)} \\\\&= 10xy^3\sqrt{4x^2y} .\end{align*} Extracting the factors that are perfect powers of the index, the expression above is equivalent to \begin{align*}\require{cancel} & 10xy^3\sqrt{(2x)^2\cdot y} \\\\&= 10xy^3(2x)\sqrt{y} \\\\&= 20x^2y^3\sqrt{y} .\end{align*} Hence, the simplified form of the given expression is $ 20x^2y^3\sqrt{y} $.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.