Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-5 Quadratic Equations - Lesson Check - Page 229: 6

Answer

$b=-1$ Since $5$ is a zero of the function, substituting $5$ to $x$ must yield $y=0$. Check the solution below.

Work Step by Step

Recall: if $a$ is a zero of the function $f(x)$, then $f(a)=0$. Hence, if $5$ is a zero of the function $y=x^2+bx-20$, then substituting $5$ to $x$ must give $y=0$: \begin{align*} y&=x^2+bx-20\\ 0&=5^2+b(5)-20\\ 0&=25+5b-20\\ 0&=5+5b\\ 0-5&=5b\\ -5&=5b\\ \frac{-5}{5}&=\frac{5b}{5}\\ -1&=b \end{align*}
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