Answer
$$−9,-4$$
Work Step by Step
A quadratic equation of the form
$$x^{2}+bx+c$$
can be factored as
$$(x+x_{1})(x+x_{2}),$$
where $x_{1}+x_{2}=b$ and $x_{1}\times x_{2}=c.$
To solve
$$x^{2}+13x=-36$$
Rewrite as
$$x^{2}+13x+36=0$$
Factor
$$x^{2}+13x+36=(x+9)(x+4)=0.$$
Hence, the solutions are
$$x=−9,-4$$
