Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-5 Quadratic Equations - Lesson Check - Page 229: 2



Work Step by Step

A quadratic equation of the form $$x^{2}+bx+c$$ can be factored as $$(x+x_{1})(x+x_{2}),$$ where $x_{1}+x_{2}=b$ and $x_{1}\times x_{2}=c.$ To solve $$x^{2}+13x=-36$$ Rewrite as $$x^{2}+13x+36=0$$ Factor $$x^{2}+13x+36=(x+9)(x+4)=0.$$ Hence, the solutions are $$x=−9,-4$$
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