Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-5 Quadratic Equations - Lesson Check - Page 229: 1



Work Step by Step

A quadratic equation of the form $$x^{2}+bx+c$$ can be factored as $$=(x+x_{1})(x+x_{2}),$$ where $x_{1}+x_{2}=b$ and $x_{1}\times x_{2}=c.$ To solve $$(x^{2}-9)=0,$$ factor $$(x^{2}-9)=(x+3)(x-3)=0.$$ Hence, the solutions are $$x=-3, 3.$$
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