Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-5 Quadratic Equations - Lesson Check - Page 229: 4

Answer

$$x \approx -1.732 \text{ and } x\approx 4.732$$

Work Step by Step

Subtract $6$ from each side of the equation to obtain: \begin{align*} x^2-3x-6&=6-6\\ x^2-3x-6&=0\\ \end{align*} Use a graphing calculator to graph $y=x^2-3x-6$. (Refer to the graph below.) The $x$-coordinate of the point/s where the graph crosses the $x$-axis ($x$-intercepts) are the solutions to the given equation. The graph crosses the $x$-axis at approximately $-1.372$ and $4.372$. Thus, the approximate solutions of the given equation are $x=-1.372$ and $x=4.372$.
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