## Algebra 2 Common Core

We simplify the expression first, then substitute the values in. We have $12(\frac{3}{4}x-\frac{1}{2}y)-6(\frac{1}{2}x-\frac{3}{4}y)=9x-6y-3x+\frac{9}{2}y=6x-\frac{3}{2}y=6(2)-\frac{3}{2}(-2)=12+3=15$