Answer
28
Work Step by Step
We substitute the values in. We have $9t+6(2v-t)-7v=9(1)+6[2(5)-(1)]-7(5)=9+6[10-1]-35=9+6(9)-35=9+54-35=63-35=28$.
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 3 - Linear Systems - Get Ready! - Page 131: 1
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