Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - Get Ready! - Page 131: 3



Work Step by Step

We substitute the values in. We have $\frac{3}{5}d+\frac{1}{10}h-\frac{7}{10}d-\frac{4}{5}h=\frac{3}{5}(5)+\frac{1}{10}(10)-\frac{7}{10}(5)-\frac{4}{5}(10)=3+1-\frac{7}{2}-8=4-\frac{7}{2}-8=4-3\frac{1}{2}-8=\frac{1}{2}-8=-7\frac{1}{2}$
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