## Algebra 2 Common Core

Published by Prentice Hall

# Chapter 3 - Linear Systems - Get Ready!: 2

45

#### Work Step by Step

We substitute the values in. We have $11(a+2b)+2(a-2b) =11[(-3)+2(4)]+2[(-3)-2(4)]=11[-3+8]+2[-3-8]=11(5)+2(-5)=55-10=45$

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