Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - Get Ready! - Page 131: 2

Answer

45

Work Step by Step

We substitute the values in. We have $11(a+2b)+2(a-2b) =11[(-3)+2(4)]+2[(-3)-2(4)]=11[-3+8]+2[-3-8]=11(5)+2(-5)=55-10=45$
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