Answer
The solution to this system of equations is $(-1, 2)$.
Work Step by Step
In the first equation, we already have an expression for $x$ that we can substitute into the second equation to find $y$. Let us do the substitution in the second equation using the expression for $x$ that was given in the first equation:
$4(y - 3) + y = -2$
Use distributive property to get rid of the parentheses:
$4y - 12 + y = -2\\
5y-12=-2$
Add $12$ to both sides to isolate constants to the right side of the equation:
$5y = -2 + 12 \\
5y=10$
Divide each side by $5$ to solve for $y$:
$y = 2$
Now that we have a value for $y$, we can substitute it into the first equation to solve for $x$:
$y-3=x\\
2 - 3 = x\\
-1=x$
Subtract to solve for $x$:
$x = -1$
The solution to this system of equations is $(-1, 2)$.
