Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - 3-3 Systems of Inequalities - Practice and Problem-Solving Exercises - Page 155: 60

Answer

$H$

Work Step by Step

We can use the point-slope form of a line because we are given a point on the graph plus the slope of the graph. The point-slope equation is as follows: $y - y_1 = m(x - x_1)$ where $(x_1, y_1)$ is a point on the graph and $m$ is the slope of the graph. Let us plug in the $x$ and $y$ coordinates of the given point and the given value of the slope into this equation: $y - (-3) = \dfrac{1}{2}(x - 4)$ Simplify using the distributive property: $y + 3 = \dfrac{1}{2}x - 4\left(\dfrac{1}{2}\right)$ Multiply to simplify the fraction: $y + 3 = \dfrac{1}{2}x - 2$ Now, we want to change this equation into slope-intercept form because all the options are in that form. The slope-intercept form of an equation is given by the following formula: $y = mx + b$ where $m$ is the slope of the line and $b$ is the y-intercept. We convert to slope-intercept form by subtracting $3$ from each side of the equation: $y = \dfrac{1}{2}x - 2 - 3$ $y = \frac{1}{2}x - 5$ This corresponds to option $H$.
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