Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - 3-3 Systems of Inequalities - Practice and Problem-Solving Exercises - Page 155: 65

Answer

This system of equations has no solution.

Work Step by Step

First, we need to rewrite the first equation into one in which one of the variables in the two equations have opposite numerical coefficients. To do this, we multiply the first equation by $2$ and obtain the equivalent system: $-2x + 10y = 6$ $2x - 10y = 4$ Add the two equations together: $(-2x+10y)+(2x-10y)=6+4\\ 0 = 10$ The resulting equation is false; therefore, this set of equations has no solution.
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