Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - 3-3 Systems of Inequalities - Practice and Problem-Solving Exercises - Page 155: 63

Answer

The solution to this system of equations is $(-9, -26)$.

Work Step by Step

In the first equation, we already have an expression for $y$ that we can substitute into the second equation to find $x$. Let us substitute $y=3x+1$ into the second equation: $2x-y=8\\ 2x - (3x + 1) = 8$ Use distributive property to get rid of the parentheses: $2x - 3x - 1 = 8\\ -x-1=8$ Add $1$ to both sides to isolate constants to the right side of the equation: $-x-1+1 =8+1\\ -x=9$ Divide both sides by $-1$ to solve for $x$: $x = -9$ Now that we have a value for $x$, we can substitute it into the first equation to solve for $y$: $y=3x+1\\ y = 3(-9) +1\\ y=-27+1\\ y=-26$ The solution to this system of equations is $(-9, -26)$.
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