Algebra 2 Common Core

\begin{align*} \text{$x$-intercept: }& \left(-\dfrac{5}{7}, 0\right) \\ \text{$y$-intercept: }& (0, 5) \end{align*}
To find the $x$-intercept of the given equation, $y=7x+5 ,$ substitute $y=0$ and then solve for $x.$ That is, \begin{align*} 0&=7x+5 \\ -7x&=5 \\\\ \dfrac{-7x}{-7}&=\dfrac{5}{-7} \\\\ x&=-\dfrac{5}{7} \end{align*} To find the $y$-intercept of the given equation, substitute $x=0$ and then solve for $y.$ That is, \begin{align*} y&=7(0)+5 \\ y&=0+5 \\ y&=5 \end{align*} Hence, the intercepts of the given equation are \begin{align*} \text{$x$-intercept: }& \left(-\dfrac{5}{7}, 0\right) \\ \text{$y$-intercept: }& (0, 5) \end{align*}