Answer
$y-2=3(x+4)$
Work Step by Step
With the given points, $(-4,2)\text{ and } (-3,5),$ then
\begin{align*}
y_1&=
2
,\\y_2&=
5
,\\x_1&=
-4
,\text{ and }\\ x_2&=
-3
.\end{align*}
Using $m=\dfrac{y_1-y_2}{x_1-x_2}$ or the Slope Formula, the slope, $m,$ of the line is
\begin{align*}\require{cancel}
m&=\dfrac{2-5}{-4-(-3)}
\\\\&=
\dfrac{2-5}{-4+3}
\\\\&=
\dfrac{-3}{-1}
\\\\&=
3
.\end{align*}
Using $
y-y_1=m(x-x_1)
$ or the Point-Slope Form of linear equations, with the point $(-4,2)$ and $m=3,$ then
\begin{align*}
y-2&=3(x-(-4))
\\\\
y-2&=3(x+4)
.\end{align*}
Hence, an equation of the line in Point-Slope Form is $
y-2=3(x+4)
.$
