Answer
$y-0=\dfrac{5}{4}(x-0)$
Work Step by Step
With the given points, $(0,0)\text{ and } (-4,-5),$ then
\begin{align*}
y_1&=
0
,\\y_2&=
-5
,\\x_1&=
0
,\text{ and }\\ x_2&=
-4
.\end{align*}
Using $m=\dfrac{y_1-y_2}{x_1-x_2}$ or the Slope Formula, the slope, $m,$ of the line is
\begin{align*}\require{cancel}
m&=\dfrac{0-(-5)}{0-(-4)}
\\\\&=
\dfrac{0+5}{0+4}
\\\\&=
\dfrac{5}{4}
.\end{align*}
Using $
y-y_1=m(x-x_1)
$ or the Point-Slope Form of linear equations, with the point $(0,0)$ and $m=\dfrac{5}{4},$ then
\begin{align*}
y-0&=\dfrac{5}{4}(x-0)
.\end{align*}
Hence, an equation of the line in Point-Slope Form is $
y-0=\dfrac{5}{4}(x-0)
.$
