## Algebra 2 Common Core

graph of $4y-x=16$:
The $x$-intercept is the value of $x$ when $y$ is $0.$ Setting $y=0$ in the given equation, $4y-x=16 ,$ results to \begin{align*} 4(0)-x&=16 \\ 0-x&=16 \\ -x&=16 \\ -1(-x)&=(16)(-1) \\ x&=-16 .\end{align*} The $x$-intercept is $( -16,0 )$. The $y$-intercept is the value of $y$ when $x$ is $0.$ Setting $x=0$ in the given equation results to \begin{align*} 4y-0&=16 \\ 4y&=16 \\\\ \dfrac{4y}{4}&=\dfrac{16}{4} \\\\ y&=4 .\end{align*} The $y$-intercept is $( 0,4 )$. Connecting the two intercepts above gives the graph of the given equation.