Answer
$y=-\frac{3}{5}(x+4)$
Work Step by Step
Recall:
The equation of a line whose slope is $m$ and passes through the point $(x_1, y_1)$ is:
$$y-y_1=m(x-x_1)$$
Thus, the equation of the line whose slope is $-\dfrac{3}{5}$ and passes through the point $(-4, 0)$ is:
\begin{align*}
y-0&=-\frac{3}{5}\left[x-(-4)\right]\\
y&=-\frac{3}{5}(x+4)
\end{align*}