Answer
$y+2=0$
Work Step by Step
Recall:
The equation of a line whose slope is $m$ and passes through the point $(x_1, y_1)$ is:
$$y-y_1=m(x-x_1)$$
Thus, the equation of the line whose slope is $0$ and passes through the point $(4, -2)$ is:
\begin{align*}
y-(-2)&=0(x-4)\\
y+2&=0
\end{align*}