Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 12 - Matrices - Mid-Chapter Quiz - Page 791: 9

Answer

$X = \begin{bmatrix} -5 & 5 & 4 \\ 7& -10& 15 \end{bmatrix}$

Work Step by Step

Using the properties of matrix equality, the given matrix equation, $ X-\begin{bmatrix} -3&2&-1 \\ 6&-7&8 \end{bmatrix} = \begin{bmatrix} -2&3&5 \\ 1&-3&7 \end{bmatrix} ,$ is equivalent to \begin{align*} X-\begin{bmatrix} -3&2&-1 \\ 6&-7&8 \end{bmatrix} + \begin{bmatrix} -3&2&-1 \\ 6&-7&8 \end{bmatrix} &= \begin{bmatrix} -2&3&5 \\ 1&-3&7 \end{bmatrix} + \begin{bmatrix} -3&2&-1 \\ 6&-7&8 \end{bmatrix} \\\\ X &= \begin{bmatrix} -2+(-3)&3+2&5+(-1) \\ 1+6&-3+(-7)&7+8 \end{bmatrix} \\\\ X &= \begin{bmatrix} -2-3&3+2&5-1 \\ 1+6&-3-7&7+8 \end{bmatrix} \\\\ X &= \begin{bmatrix} -5 & 5 & 4 \\ 7& -10& 15 \end{bmatrix} .\end{align*} Hence, $ X = \begin{bmatrix} -5 & 5 & 4 \\ 7& -10& 15 \end{bmatrix} .$
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