Answer
No, he's not correct.
$n=\frac{s}{1-s}$, not $\frac{s}{s-1}$
Work Step by Step
$s=\frac{n}{n+1}$
$s(n+1)=n$
$sn+s=n$
$s=n-sn$
$s=n(1-s)$
$\frac{s}{1-s}=n$
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 1 - Expressions, Equations, and Inequalities - 1-4 Solving Equations - Practice and Problem-Solving Exercises - Page 31: 63
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