## Algebra 2 Common Core

solution of the equation: m=$\frac{23}{3}$
original equation: $(m-2)-5=8-2(m-4)$ Distribute the -2 to each term of $m-4$ : $(m-2)-5=8-2m+8$ Move terms with the varible "m" to one side and terms with no variable to the other side to simplify (add 2m and 5 to both sides) $(m-2)+2m=8+8+5$ Combine like terms: $3m-2 = 16 + 5 \\3m - 2 = 21$ Again, move the terms with the variable to one side and those without the variable to the other side (add 2 to both sides): $3m= 23$ Divide both sides by 3 to isolate m: $3m \div3 =23 \div3$ Final solution: $m = \frac{23}{3}$