## Algebra 2 Common Core

$43, 45, 47, 49$
Start with the equation; $(x)+(x+2)+(x+4)+(x+6)=184$ where $x$ is the smallest odd number among the four. We have a base number $x$ and 3 consecutive odds above it. Combining like terms brings us to $4x=172$. Divide both sides by $4$, and we find $x=43$. The three consecutive odd integers above it are $45, 47,$ and $49$