## Algebra 2 Common Core

$x=\frac{3bc−4a}{−aq+5bp}$
We start by distributing. We have $5bpx−3bc=aqx−4a$. We want to be able to factor out x so we move the terms with x to one side and the terms without x to the other side. We will add $-aqx$ and $3bc$ to both sides to get $−aqx+5bpx=3bc−4a$. Now we factor out x to get $x(−aq+5bp)=3bc−4a$. Finally, we divide both sides by $−aq+5bp$ to isolate x. $x=\frac{3bc−4a}{−aq+5bp}$