## Algebra 2 (1st Edition)

Solving for x, we find: $$\frac{x-4}{x-3}\left(x-3\right)+2\left(x-3\right)=\frac{2x-3}{x-3}\left(x-3\right)\\ x-4+2\left(x-3\right)=2x-3 \\ x=7$$