## Algebra 2 (1st Edition)

$$2\left(x+2\right)$$
Simplifying the equation by cancelling out factors, we find: $$\frac{\left(2x+8\right)}{x-3}\times \frac{x^2-x-6}{\left(x+4\right)}\\ \frac{2\left(x+2\right)\left(x-3\right)}{x-3}\\ 2\left(x+2\right)$$