## Algebra 2 (1st Edition)

The length is $115$ and the width is $75.$
Let $x$ be the length. Then the width is $x-40$. But we know that the circumference is $380$, thus: $x+(x-40)+x+(x-40)=380\\4x=460\\x=115$. Thus the length is $115$, and the width is $75.$