Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Cumulative Review - Page 678: 5

Answer

$$x=\frac{9+\sqrt{241}}{4},\:x=\frac{9-\sqrt{241}}{4}$$

Work Step by Step

Solving the equation, we find: $$4x^2-18x-40=0\\ x=\frac{-\left(-18\right)+\sqrt{\left(-18\right)^2-4\cdot \:4\left(-40\right)}}{2\cdot \:4}\\ x=\frac{9+\sqrt{241}}{4},\:x=\frac{9-\sqrt{241}}{4}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.

GradeSaver will pay $15 for your literature essays
GradeSaver will pay $25 for your college application essays
GradeSaver will pay $50 for your graduate school essays – Law, Business, or Medical
GradeSaver will pay $10 for your Community Note contributions
GradeSaver will pay $500 for your Textbook Answer contributions