Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Cumulative Review - Page 678: 5



Work Step by Step

Solving the equation, we find: $$4x^2-18x-40=0\\ x=\frac{-\left(-18\right)+\sqrt{\left(-18\right)^2-4\cdot \:4\left(-40\right)}}{2\cdot \:4}\\ x=\frac{9+\sqrt{241}}{4},\:x=\frac{9-\sqrt{241}}{4}$$
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