Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.1 Apply the Distance and Midpoint Formulas - 9.1 Exercises - Mixed Review - Page 619: 67



Work Step by Step

Using the quadratic formula in order to solve the equation, we find: $$x_{1,\:2}=\frac{-\left(-13\right)\pm \sqrt{\left(-13\right)^2-4\cdot \:12\cdot \:3}}{2\cdot \:12} \\ x=\frac{3}{4},\:x=\frac{1}{3}$$
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