Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.1 Apply the Distance and Midpoint Formulas - 9.1 Exercises - Mixed Review - Page 619: 74



Work Step by Step

Solving the equation using the rules of Algebra, we find: $$\frac{x-6}{x-3}=\frac{x-2}{x+4} \\ \left(x-6\right)\left(x+4\right)=\left(x-3\right)\left(x-2\right) \\ x^2-2x-24=x^2-5x+6 \\ x=10$$
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