Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.1 Apply the Distance and Midpoint Formulas - 9.1 Exercises - Mixed Review - Page 619: 72



Work Step by Step

Solving the equation using the rules of Algebra, we find: $$\left(\sqrt{x-3}\right)^2=\left(x-5\right)^2 \\ x-3=x^2-10x+25 \\ x=7,\:x=4$$ We see that $x=4$, however, is extraneous, so it is not a solution.
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