Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.1 Apply the Distance and Midpoint Formulas - 9.1 Exercises - Mixed Review - Page 619: 66

Answer

$$x=-\frac{5}{8},\:x=-4$$

Work Step by Step

Using the quadratic formula in order to solve the equation, we find: $$x_{1,\:2}=\frac{-37\pm \sqrt{37^2-4\cdot \:8\cdot \:20}}{2\cdot \:8} \\ x=-\frac{5}{8},\:x=-4$$
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