Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.4 Factor and Solve Polynomial Equations - 5.4 Exercises - Skill Practice - Page 357: 52

Answer

$x=5$

Work Step by Step

According to the exercise our equation is: $2x(x-1)(x-4)=40\\x(x-1)(x-4)=20\\x(x^2-5x+4)=20\\x^3-5x^2+4x-20=0\\(x-5)(x^2+4)$ Thus $x^2+4=0$ (but this is impossible since $x^2$ is non-negative) or $x-5=0\\x=5$
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