Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.4 Factor and Solve Polynomial Equations - 5.4 Exercises - Skill Practice - Page 357: 51



Work Step by Step

According to the exercise our equation is: $(x+4)(3x+2)=48\\3x^2+2x+12x+8=48\\3x^2+14x-40=0\\(x-2)(3x+20)=0$ Thus $3x+20=0$, hence $x=-\frac{20}{3}$ (but this gives negative lengths for the sides, thus it is not a good solution) or $x-2=0\\x=2$
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