Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.4 Factor and Solve Polynomial Equations - 5.4 Exercises - Skill Practice - Page 357: 39


$x=\pm\sqrt3$ or $x=2$ or $x=-2$

Work Step by Step

$x^6-4x^4-9x^2+36=(x-2)(x+2)(x^2-3)(x^2+3)=0$ Thus $x^2+3=0$ (but this is impossible since $x^2$ is non-negative) or $x^2-3=0\\x^2=3\\x=\pm\sqrt3$ or $x-2=0\\x=2$ or $x+2=0\\x=-2$
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