## Algebra 2 (1st Edition)

$$x=2.25\pm .25\sqrt{15}i$$
When given the choice to use any method, the quadratic formula is a good choice because it will always work. We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain: $$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$ $$x=\frac{9\pm \sqrt{(-9)^2-4(2)(12)}}{2(2)}$$ $$x=2.25\pm .25\sqrt{15}i$$