Chapter 4 Quadratic Functions and Factoring - 4.8 Use the Quadratic Formula and the Discriminant - 4.8 Exercises - Skill Practice - Page 296: 42

$$x=1.75\pm.25\sqrt{41}$$

Work Step by Step

When given the choice to use any method, the quadratic formula is a good choice because it will always work. We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain: $$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$ $$x=\frac{7\pm \sqrt{(-7)^2-4(2)(1)}}{2(2)}$$ $$x=1.75\pm.25\sqrt{41}$$

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