Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.8 Use the Quadratic Formula and the Discriminant - 4.8 Exercises - Skill Practice - Page 296: 22

Answer

$$z=-7,\:z=-8$$

Work Step by Step

Solving the equation using the quadratic formula, we find: $$z_{1,\:2}=\frac{-15\pm \sqrt{15^2-4\cdot \:1\cdot \:56}}{2\cdot \:1} \\ z=-7,\:z=-8$$ Checking by factoring the expression, we find: $$z\left(z+7\right)+8\left(z+7\right) \\ \left(z+7\right)\left(z+8\right)$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.