Two imaginary solutions
Work Step by Step
We first check that the function is in the form $ax^2+bx+c$. We know that the discriminant is in the form $b^2-4ac$. If this is positive, there are two real solutions. If this is 0, there is one real solution. If this is negative, there are two imaginary solutions. Thus, we find: $$1^2-4(-4)(-14)=-223$$ Thus, there are two imaginary solutions.