Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.10 Write Quadratic Functions and Models - 4.10 Exercises - Skill Practice - Page 313: 41

Answer

$f(x)=8(x+11)(x-3)$.

Work Step by Step

If the x-intercepts of a graph are $a,b$, then the function has the form $f(x)=k(x-a)(x-b)$. The x-intercepts are -11, 3, hence the quadratic function becomes $f(x)=k(x+11)(x-3)$. The point (1,-192) is on the graph, hence if we plug in the values we get $-192=k(12)(-2)$. This yields k=8, hence $f(x)=8(x+11)(x-3)$.
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