## Algebra 2 (1st Edition)

$y=-2(x+5)(x+1)$
We already know $y$, $x$, $p$ and $q$ from the given x-intercepts and the point, so in order to get the quadratic function we need to find $a$... $y=a(x-p)(x-q)$ $-24=a(-7+5)(-7+1)$ $-24=12a$ $a=-\frac{24}{12}$ $a=-2$ Therefore the function is... $y=-2(x+5)(x+1)$