## Algebra 2 (1st Edition)

$$x=-5/6\pm (1/6)\sqrt{23}i$$
We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain: $$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$ $$x=\frac{-5\pm \sqrt{(5)^2-4(3)(4)}}{2(3)}$$ $$x=-5/6\pm (1/6)\sqrt{23}i$$