Answer
See below
Work Step by Step
Given: $y_0=5$ ft
$v_0=30$ ft/sec
The position of the ball is $y=y_0+v_0t-16t^2$
Set $y=0$,
$16t^2-30t-5=0\\
\rightarrow t=\frac{15 \pm \sqrt 305}{16}$
We will take only positive values: $t \approx 2029$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 4 Quadratic Functions and Factoring - 4.10 Write Quadratic Functions and Models - 4.10 Exercises - Quiz for Lessons 4.8-4.10 - Page 315: 13
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