#### Answer

$$x=2\pm .5\sqrt{14}$$

#### Work Step by Step

We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain:
$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
$$x=\frac{8\pm \sqrt{(-8)^2-4(2)(1)}}{2(2)}$$
$$x=2\pm .5\sqrt{14}$$