Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.10 Write Quadratic Functions and Models - 4.10 Exercises - Quiz for Lessons 4.8-4.10 - Page 315: 1


no solution.

Work Step by Step

The quadratic formula says that for $ax^2+bx+x$: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$. Hence here $x=\frac{4\pm\sqrt{(-4)^2-4(1)(5)}}{2(1)}=\frac{4\pm\sqrt{16-20}}{2(1)}$ As we can see the discriminant is negative, thus there is no solution.
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