Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.6 Multiplying Matrices - 3.6 Exercises - Skill Practice - Page 200: 25

Answer

$AB-BA=\begin{bmatrix} -10 &7\\ -8& 10 \end{bmatrix}$

Work Step by Step

$AB=\begin{bmatrix} -12 &11\\ 16& -10 \end{bmatrix}$ $BA=\begin{bmatrix} 0 & 1\\ 4 & -2 \end{bmatrix}.\begin{bmatrix} 5& -3\\ -2 & 4 \end{bmatrix}$ $=\begin{bmatrix} 0.5+1.(-2) &0.(-3)+1.4\\ 4.5-2.(-2) & 4.(-3)-2.4 \end{bmatrix}$ $=\begin{bmatrix} -2 &4\\ 24 & -20 \end{bmatrix}$ $AB- BA=\begin{bmatrix} -12 &11\\ 16& -10 \end{bmatrix}-\begin{bmatrix} -2 &4\\ 24 & -20 \end{bmatrix}$ $=\begin{bmatrix} -12-(-2) &11-4\\ 16-24 & -10-(-20) \end{bmatrix}$ $=\begin{bmatrix} -10 &7\\ -8& 10 \end{bmatrix}$
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