Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.6 Multiplying Matrices - 3.6 Exercises - Skill Practice - Page 200: 22

Answer

$3AB=\begin{bmatrix} -36 & 33 \\ 48 & -30 \end{bmatrix}$

Work Step by Step

$3AB=3\begin{bmatrix} 5 & -3 \\ -2 & 4 \end{bmatrix} \times \begin{bmatrix} 0 & 1 \\ 4 & -2 \end{bmatrix}$ $=\begin{bmatrix} 15 & -9 \\ -6 & 12 \end{bmatrix} \times \begin{bmatrix} 0 & -1 \\ 4 & -2 \end{bmatrix}$ $=\begin{bmatrix} (15\times0)+(-9\times4) & (15\times1)+(-9\times(-2)) \\ (-6\times0)+(12\times4) & (-6\times1)+(12\times(-2)) \end{bmatrix} $ $=\begin{bmatrix} -36 & 33 \\ 48 & -30 \end{bmatrix}$
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