Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.6 Multiplying Matrices - 3.6 Exercises - Skill Practice - Page 200: 24

Answer

$AB+AC=\begin{bmatrix} -54 & 23\\ 44 & -12 \end{bmatrix}$

Work Step by Step

$AB=\begin{bmatrix} 5 & -3\\ -2 & 4 \end{bmatrix}\times\begin{bmatrix} 0 & 1\\ 4 & -2 \end{bmatrix}$ $=\begin{bmatrix} 5.0-3.4 & 5.1-3.(-2)\\ -2.0+4.4&-2.1+4.(-2) \end{bmatrix}$ $=\begin{bmatrix} -12 & 11\\ 16 & -10 \end{bmatrix}$ $AC=\begin{bmatrix} 5 & -3\\ -2 & 4 \end{bmatrix}\times\begin{bmatrix} -6 & 3\\ 4 & 1 \end{bmatrix}$ $=\begin{bmatrix} 5.(-6)-3.4 & 5.3-3.1\\ -2.(-6)+4.4&-2.3+4.1 \end{bmatrix}$ $=\begin{bmatrix} -42 & 12\\ 28 & -2 \end{bmatrix}$ $AB+AC=\begin{bmatrix} -12 & 11\\ 16 & -10 \end{bmatrix}+\begin{bmatrix} -42 & 12\\ 28 & -2 \end{bmatrix}$ $=\begin{bmatrix} -12-42 & 11+12\\ 16+28 & -10-2 \end{bmatrix}$ $=\begin{bmatrix} -54 & 23\\ 44 & -12 \end{bmatrix}$
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