Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.4 Evaluate Inverse Trigonometric Functions - 13.4 Exercises - Skill Practice - Page 878: 9


$\theta=-\dfrac{\pi}{6}$ or, $-30^{\circ}$

Work Step by Step

We are given $\tan^{-1} (-\dfrac{\sqrt 3}{3})$ We know that the trigonometric function $\tan^{-1}$ has domain R and the range is: $[-\dfrac{\pi}{2}, \dfrac{\pi}{2}]$. So, $\theta = \tan^{-1}(-\dfrac{\sqrt 3}{3})$ This implies that: $\theta=-\dfrac{\pi}{6}$ or, $-30^{\circ}$
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