Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.4 Evaluate Inverse Trigonometric Functions - 13.4 Exercises - Skill Practice - Page 878: 23



Work Step by Step

Let us consider $\tan \theta =3.2$ ; $180^{\circ} \lt \theta \lt 270^{\circ}$ Then, our result will be: $\theta \approx 72.65^{\circ}$ But, the angle $\theta$ does not belong to the interval $(180^{\circ} , 270^{\circ})$, so we will compute the reference angle that lies in the given interval. Then we have: $\theta = 72.65^{\circ}+180^{\circ}=252.65^{\circ}$
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